rapping Rain Water

Given an array arr[] of N non-negative integers representing the height of blocks. If width of each block is 1, compute how much water can be trapped between the blocks during the rainy season. 

 

Example 1:

Input:
N = 6
arr[] = {3,0,0,2,0,4}
Output:
10
Explanation:

Example 2:

Input:
N = 4
arr[] = {7,4,0,9}
Output:
10
Explanation:
Water trapped by above 
block of height 4 is 3 units and above 
block of height 0 is 7 units. So, the 
total unit of water trapped is 10 units.

Example 3:

Input:
N = 3
arr[] = {6,9,9}
Output:
0
Explanation:
No water will be trapped.


Your Task:
You don'y need to read input or print anything. The task is to complete the function trappingWater() which takes arr and N as input parameters and returns the total amount of water that can be trapped.



 self.arr=arr
        self.n=n
        a=arr
     
    # For every element of the array
        lmax=a[0]
        rmax=max(a[1:])
        count=0
        for i in range(n):
            if(a[i]>lmax):
                lmax=a[i]
            if(a[i]==rmax and i<n-1):
                rmax=max(a[i+1:])
            h=min(lmax,rmax)
            count+=max(h-a[i],0)
        return (count)
 

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